# Line slope calculator x+5y=8

**Straight line given by points A[3; 1] and B[8; 0]**

## Calculation:

**Slope-intercept form of line:**y = -0.2x+1.6

**Canonical form of the line equation:**x+5y-8 = 0

**Parametric form of the line equation:**

x = 5t+3

y = -t+1 ; t ∈ R

**Slope:**m = -0.2

**Slope angle of line: φ =**-11°18'36″ = -0.1974 rad

**X intercept:**x

_{0}= 8

**Y intercept:**y

_{0}= q = 1.6

**Distance line from the origin:**d

_{0}= 1.5689

**The length of the segment AB: |AB| =**5.099

**Vector: AB =**(5; -1)

**Normal vector: n =**(1; 5)

**Midpoint of the segment AB: M =**[5.5; 0.5]

**Perpendicular Bisector equation:**5x-y-27 = 0

**Vector OA = (3; 1) ; |OA| = 3.1623**

**Vector OB = (8; 0) ; |OB| = 8**

**Scalar product OA .OB = 24**

**Angle ∠ AOB = 18°26'6″ = 0.3218 rad**